Math, asked by tanishqharsh375, 15 days ago

find the greatest number which divides 2021 and 623 leaving remainders 4.5.6 respectively​

Answers

Answered by beingshalinisingh
1

Step-by-step explanation:

Correct option is

A

12

The required greatest number=H.C.F of (148−4),(246−6),(623−11)

                                                = H.C.F of 144,240,612

Here, the HCF of 144,240,and612 is

21442406122721203063

3660153

122051H.C.F=2×2×3=12

∴ The required number is 12.

Answered by sk4023659
1

Answer:

The required greatest number=H.C.F of (148−4),(246−6),(623−11)

= H.C.F of 144,240,612

Here, the HCF of 144,240,and612 is

2 144 240 612

2 72 120 306

3

36 60 153

12 20 51

H.C.F=2×2×3=12

∴ The required number is 12.

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