Math, asked by ekradhe149, 5 hours ago

find the greatest number which divides 203 & 434 Leaving remainder 5 in each case ??
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Answers

Answered by samraggibasak
3

Answer:

429

Step-by-step explanation:

434 ÷429=5

434-5=429

Answered by Anonymous
36

GivEn:

  • There is a greatest number which divides 203 & 434 Leaving remainder 5 in each case.

To find:

  • The greatest number.

Solution:

• First let's subtract 5 from 203 & 434, As it is given that, It gives reminder 5 if 203 & 434 are divided by that number.

⠀⠀━━━━━━━━━━━━━━━━━━━⠀

« Now, Finding the number,

• Subtracting,

203 - 5 = 198

434 - 5 = 429

As we know that,

  • To find the number we need find prime factors of the difference obtained,

• We get,

198 = 2 × 3 × 3 × 11

429 = 3 × 11 × 13

⠀⠀━━━━━━━━━━━━━━━━━━━⠀

« Now, Finding highest common factors,

• HCF of 198 and 203,

→ 33

∴ Hence, 33 is the greatest number which divides 203 and 434 leaving remainder 5 in each case.

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