Math, asked by puspak64, 1 year ago


Find the greatest
number which divides 203 and 434 leaving remainder 5 in each
case.​

Answers

Answered by argha16
16

Answer:

33

Step-by-step explanation:

203-5=198

434-5=429

now the HCF of 198 and 429 is 33

so the greatest no is 33

Answered by Anonymous
7

Question:

Find the greatest number which divides 203 and 434 leaving remainder 5 in each case.

Answer:

  • 33

Solution:

Given the number 203 and 434 leaving remainder 5 in each case respectively:-

The numbers that are exactly divisible are:-

= 203 - 5 = 198

= 434 - 5 = 429

The prime factors of 198 and 429 are :-

= 198 = 2 × 3 × 3 × 1 × 1

= 429 = 3 × 11 × 13

★.HCF (198,429) = 3 × 11 = 33

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