Find the greatest
number which divides 203 and 434 leaving remainder 5 in each
case.
Answers
Answered by
16
Answer:
33
Step-by-step explanation:
203-5=198
434-5=429
now the HCF of 198 and 429 is 33
so the greatest no is 33
Answered by
7
Question:
Find the greatest number which divides 203 and 434 leaving remainder 5 in each case.
Answer:
- 33
Solution:
Given the number 203 and 434 leaving remainder 5 in each case respectively:-
The numbers that are exactly divisible are:-
= 203 - 5 = 198
= 434 - 5 = 429
The prime factors of 198 and 429 are :-
= 198 = 2 × 3 × 3 × 1 × 1
= 429 = 3 × 11 × 13
★.HCF (198,429) = 3 × 11 = 33
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