Math, asked by rakeshrei15, 6 months ago

Find the greatest number which divides 203 and 434 leaving remainder 5 in each
case.

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Answered by Anonymous

Answer:

The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429. Prime factorization of 429 = 3 * 11 * 13. = 33. Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33.

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Find the greatest number which divides 203 and 434 leaving remainder 5 in eachcase.​

Answers

Find the greatest number which divides 203 and 434 leaving remainder 5 in each
case.