Question

find the greatest number which divides 203 and 434 leaving remainder 5 in each case

Answer 1

Heya !

Question
-Find the greatest number which divides 203 and 434 leaving remainder 5 in each case

ANSWER ↓

Given
-The numbers 203 and 434 leaving remainder 5 in each case respectively.

Solution
-Step 1 - Substract 5 from each case
203 - 5 = 198 and 434 - 5 = 429

-Step 2 - Prime Factorise both of them
Prime factorization of 198 = 2 × 3 × 3 × 11
Prime factorization of 429 = 3 × 11 × 13

-Step 3 - Find the HCF (Highest Common Factor)
HCF = 3 and 11
=3 × 11
=33

∴the largest number which divides 203 and 434 leaving remainder 5 in each case = 33.


Hope this helps!
@PoojaBBSR

Answer 2

the numbers that are exactly divisible are 203-5=198 and 434-5=429
factors of 198=2,3,3,11
factors of 429=3,11,13
HCF=3×11=33
the greatest no which divides this 33 leaves remainder 5