find the greatest number which divides 203 and 434 leaving reminder 5 in each case..
Plz can you send me picture of the answer i will mark you as a brainlist
Answers
Answered by
0
Answer:
33
Step-by-step explanation: Given that the numbers 203 and 434 leaving remainder 5 in each case respectively.
The numbers that are exactly divisible are 203 - 5 = 198 and 434 - 5 = 429.
Prime factorization of 198 = 2 * 3 * 3 * 11
Prime factorization of 429 = 3 * 11 * 13.
HCF(198,429) = 3 * 11
= 33.
Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33.
Answered by
0
Answer:
6383e8evdbdbdid9e0e9eieieieoeoe9e9e
Similar questions