Question

find the greatest number which divides 203 and 434 leaving reaminder 5 in each case

Answer 1

Answer:

The numbers that are exactly divisible are 203 / 5 = 198

and 434 / 5 = 429.

Prime factorization of 429 = 3 * 11 * 13. = 33.

Therefore the largest number which divides 203 and 434 leaving remainder 5 in each case = 33

Step-by-step explanation:

Hope the answer is satisfactory

please mark me brainliest.