find the greatest number which divides 203 and 434 leaving remainder as 5 in each case by continued division meathod
it is very urgent
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Numbers change hogaya hai
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The greatest number which divides 134 and 167 leaving 2 as remainder in each case is
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Correct option is D)
Since we require 2 as the remainder we will subtract 2 from each of the numbers
167−2=165
134−2=132
Now any of the common factors of 165 and 132 will be the required divisor
On factorization
165=3×5×11
132=2×2×3×11
Their common factors are 11 and 3=11×3=33
Hence 33 is the required divisor
Option (d) is the correct answer
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