Find the greatest number which divides 243 and 1029 leaving remainders 3&5
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Step-by-step explanation:
To find this answer we need to subtract 3 from 243 and 5 from 1029
and Find their HCF
i.e HCF(240 , 1024)
240 = 2^4 x 3 x 5
1024 = 2^10
As Hcf is the product of lowest power of common prime factors
hcf( 240 , 1024) = 2^4 =16
So 16 is the greatest number which divides 243 and 1029 leaving remainder 3 &5 respectively
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Answer:
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