Find the greatest number which divides 244 and 4780 leaving remainders 4 in each case
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Answer:
216
Step-by-step explanation:
since the remainder is 4 in each case
244 –4=240
4780-4=4776
240)4776(19
4560
216)240(1
216
24)216(9
216
0
By Euclid's division algorithms
4776=240 x 19+216
240=216 x 1+24
216 =24 x 9+0
Therefore the greatest number =24
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