Question

find the greatest number which divides 2706 7041 and,8250 leaving remainder 6,21 and 42 respectively.
Please answer my question​

Answer 1

First , we find the least number which is exactly divisible by the numbers 18,21,28 and 30 . For this , we find the L.C.M of 18,21,28 and 30.

∴ L.C.M =2×2×3×3×5×7=1260

According to given , the required will be 20 more than 1260.

The required number =1260+20=1280

Answer 2

Answer:

please mark as branliest answer and follow me PLZZ.

.