Question

find the greatest number which divides 279 and 435 leaving and remainder 7 and 10 respectively

Answer 1

Numbers which will be divided,
279 - 7 = 272
435 - 10 = 425

=================

272 = 2 × 2 × 2 × 2 × 2 × 17
425 = 5 × 5 × 17

HCF = 17

Then, 17 is the largest number which is required here

I hope this will help you


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Answer 2

Heya !!!


279 - 7 = 272



And,




435 - 10 = 425


Prime factorisation of 272 = 2 × 2 × 2 × 2 × 7



Prime factorisation of 425 = 5 × 5 × 17



HCF of 272 and 425 = 17



Therefore,


Required greatest Number = 17.




HOPE IT WILL HELP YOU....... :-)