Find the greatest number which divides 280 and 1245, leaving remainders 4 and 3, respectively
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First of all, we need to subtract the remainders
Prime factorisation:-
276 = 2 x 2 x 3 x 23
1242 = 2 x 3 x 3 x 3 x 23
HCF = 138
Hope it’ll help
Prime factorisation:-
276 = 2 x 2 x 3 x 23
1242 = 2 x 3 x 3 x 3 x 23
HCF = 138
Hope it’ll help
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