Question

find the greatest number which divides 281 and 141 leaving remainder 5

Answer 1

ᴴᴱᵞᴬ!!

ᴴᴱᴿᴱ ᴵˢ ᵀᴴᴱ ᴬᴺˢᵂᴱᴿ

ᴾᴱᴿᶠᴱᶜᵀ ᴺᵁᴹᴮᴱᴿˢ ᵂᴴᴵᶜᴴ ᴬᴿᴱ ᴰᴵᵛᴵˢᴵᴮᴸᴱ ᵂᴵᵀᴴᴼᵁᵀ ᴸᴱᴬᵛᴵᴺᴳ ᴿᴱᴹᴬᴵᴺᴰᴱᴿ :-

281 - 5 = 276

ᴬᴺᴰ

141 - 5 = 136

ᴺᴼᵂ

ᵂᴱ ᴴᴬᵛᴱ ᵀᴼ ᶠᴵᴺᴰ ᵀᴴᴱ ᴴ. ᶜ. ᶠ. (ᴴᴵᴳᴴᴱˢᵀ ᶜᴼᴹᴹᴼᴺ ᶠᴬᶜᵀᴼᴿ)

276 = 2 × 2 × 3 × 23

136 = 2 × 2 × 2 × 17

ᴴ. ᶜ. ᶠ. = 2 × 2 = 4.

ᴴᴱᴺᶜᴱ, ᵀᴴᴱ ᴳᴿᴱᴬᵀᴱˢᵀ ᴺᵁᴹᴮᴱᴿ ᴵˢ 4.

ᴴᴼᴾᴱ ᵀᴴᴵˢ ᴴᴱᴸᴾˢ.