Find the greatest number which divides 284, 678 and 1618 leaves the same remainder in each case.
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35
The greatest number which when divides 253,568 and 813 leaves the same remainder each time
→ HCF of (568−253),(813−568),(813−253)= HCF of 315,245 and 560
Prime factorisation of 315,245 and 560 is,
315=3×3×5×7
245=7×7×5
560=2×2×2×2×5×7
Therefore HCF of 315,245 and 560 is 5×7=35.
The greatest number which when divides 253,568 and 813 leaves the same remainder each time is 35 and the remainder obtained in each case is 8.
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