find the greatest number which divides 285 and 1249 leaving remainder 9 and 7 respectively .
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Hey!!
Required number ( 285 - 9 ) = 276, ( 1249 - 7 ) = 1242
So, the required number are 276 and 1242
By prime factorization method
276 = 2 × 2 × 3 × 23
1242 = 2 × 3 × 3 × 3 × 23
Therefore, HCF[ 2 × 3 × 23 ] = 138>>>> Answer
___________________________
Hope it will helps you :-)
Required number ( 285 - 9 ) = 276, ( 1249 - 7 ) = 1242
So, the required number are 276 and 1242
By prime factorization method
276 = 2 × 2 × 3 × 23
1242 = 2 × 3 × 3 × 3 × 23
Therefore, HCF[ 2 × 3 × 23 ] = 138>>>> Answer
___________________________
Hope it will helps you :-)
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1
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