Find the greatest number which divides 290 and 538 leaving remainder 3 and 5
Answers
Answered by
57
Hi friend
Here's your answer looking for
First let subtract the given reminder with respective numbers.
290-3=287
And,
538-5=533
Now, let's find the HCF of 287 and 533.
287= 7×41
533= 13×41
So,
HCF = 41
And 41 is the required number.
Hope you are satisfied with my answer
Here's your answer looking for
First let subtract the given reminder with respective numbers.
290-3=287
And,
538-5=533
Now, let's find the HCF of 287 and 533.
287= 7×41
533= 13×41
So,
HCF = 41
And 41 is the required number.
Hope you are satisfied with my answer
Answered by
4
Answer:
Hi friend
Here's your answer looking for
Step-by-step explanation: First let subtract the given reminder with respective numbers.
290-3=287
And,
538-5=533
Now, let's find the HCF of 287 and 533.
287= 7×41
533= 13×41
So,
HCF = 41
And 41 is the required number.
Hope you are satisfied with my answer
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