find the greatest number which divides 399 434 and 537 leaving the remainder 8 9 and 10 respectively ?
Answers
Answer:
The number divides 399,434 and 537 leaving the remainder 8,9 and 10.
The number divides 399,434 and 537 leaving the remainder 8,9 and 10.So, that number will divide (399−8),(434−9) and (537−10) completely.
The number divides 399,434 and 537 leaving the remainder 8,9 and 10.So, that number will divide (399−8),(434−9) and (537−10) completely.Now, the greatest number that will divide 391,425 and 527 completely, is the H.C.F. of these numbers.
The number divides 399,434 and 537 leaving the remainder 8,9 and 10.So, that number will divide (399−8),(434−9) and (537−10) completely.Now, the greatest number that will divide 391,425 and 527 completely, is the H.C.F. of these numbers.391=17×23
The number divides 399,434 and 537 leaving the remainder 8,9 and 10.So, that number will divide (399−8),(434−9) and (537−10) completely.Now, the greatest number that will divide 391,425 and 527 completely, is the H.C.F. of these numbers.391=17×23425=5×5×17
The number divides 399,434 and 537 leaving the remainder 8,9 and 10.So, that number will divide (399−8),(434−9) and (537−10) completely.Now, the greatest number that will divide 391,425 and 527 completely, is the H.C.F. of these numbers.391=17×23425=5×5×17527=17×31
The number divides 399,434 and 537 leaving the remainder 8,9 and 10.So, that number will divide (399−8),(434−9) and (537−10) completely.Now, the greatest number that will divide 391,425 and 527 completely, is the H.C.F. of these numbers.391=17×23425=5×5×17527=17×31H.C.F. =17
Answer:
FIND THE GREATEST NO WHICH DEVIDES 399, 434, AND 537 LEAVING THE REMAINDERS 8, 9 AND 10 RESPECTIVELY. so the number that will divide 399,434,537 leaving remainder 8,9 and 10 respectively is 17.