find the greatest number which divides 418 1354 2146 and 2338 exactly leaving remainder 10
in each case
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418,1354,2146,2338
remainder-10 each in every number
then 418-10=408
1354-10=1344
2146-10=2136
2338-10=2328
and then solve the hcf(408,1344,2136,2328)
and that's answer
remainder-10 each in every number
then 418-10=408
1354-10=1344
2146-10=2136
2338-10=2328
and then solve the hcf(408,1344,2136,2328)
and that's answer
sudhanshutiwari:
bhai hcf bhi nikal de divisble method se
245= 16×5+5. , 1029=16×64+5
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1
Answer:
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