find the greatest number which divides 42 62 and 99 leaving remainder 7 8 and 9 respectively.
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Answered by
1
Answer:
Correct option is
C
45
Required number=HCFof(3026−11,5053−11)=HCFof(3015,5040)
3015=3×3×5×67=3
2
×5×67
5040=2×2×2×2×3×3×5×7=2
4
×3
2
×5×7
∴ HCF of (3015,5040)=3
2
×5=9×5=45
Hence the greatest number is 45.
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Answer:
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