Math, asked by manjunayak7114, 3 months ago

Find the greatest number which divides 455 606 907 and leaving remainders 5 6 and 7 respectively​

Answers

Answered by Anonymous
0

Answer:

445−4=441

572−5=567

699−6=693

The greatest common factors of 441, 567 and 693 is,

441=3×3×7×7

567=3×3×3×3×7

693=3×3×7×11

The common factors are 3×3×7=63.

63

445

=7 with remainder as 4.

63

572

=9 with remainder as 5.

63

699

=11 with remainder as 6.

Therefore, 63 is the greatest number.

Answered by Dilana
0

Answer:

150 is the greatest number

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