Question

find the greatest number which divides 47,67 and 107 leaving a remainder 7 in each case.​

Answer 1

Answer:

Step-by-step explanation:

First subtract 7 from each

So now the numbers are 40,60,100

Find there HCF

10

Hence 10 is the number

Let's verify

47/10

67/10

107/10

All leave 7 as remainder

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