Question

find the greatest number which divides 47 ,74 and 101 leaving the remainder 2 in each case ​

Answer 1

Answer:

Here, The required number is 9.

Step-by-step explanation:

Here, As given in question,

=47-2=45

=74-2=72

=101-2=99

Now, Prime factors of all given numbers are:

=45=3×3×5

=72=2×2×2×3×3

=99=3×3×11

Now, As we have to find out the greatest number, we would find HCF of the numbers.

=So, Hcf=3×3×=9

So, 9 us the greatest number which divides 47, 74 and 101 leaving remainder 2 in each case.

Thank you.

Answer 2

Answer:

hey..bhaisnavi...u can thank ayeong07 answer afterwards..plsss..

now she is not in the mood..plss

understand.. it's humble request...

u r really sweet.❤️❤️

purple you forever.❤️❤️❤️