Question

find the greatest number which divides 4878 and 123 leaving remainder 3

Answer 1

Here's your answer!!

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To find the number which divides 4878 and 123 leaving remainder 3 ,we will have to first subtract 3 from both then find their HCF.

$= > 4878 - 3 \\ = > 4875$
$= > 123 - 3 \\ = > 120$
Now,
We will find HCF :-

$= > 4875 = 3 \times 5 \times 13 \\ = > 120 = 2 \times 3 \times 5$
So,
HCF = 3×5
$= > 15$
Hence,
The greater number which when divided by 4878 and 123 ,leaves remainder 3 in both case is ,"15".

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Hope it helps you!! :)