find the greatest number which divides 615 and 963 leaving the remainder 6 in each case
Answers
Answered by
2
Answer:
303 and 319
Step-by-step explanation:
it will leave rhe remainder 6 in both the cases.......
Answered by
1
Answer:
3
Step-by-step explanation:
the greatest no. which divides the 615 and 963 leaving remainder 6 will be
first of all if we add 6 to both no. then they are completely divisible by the no and we know greatest no. which divides is the HCF
therefore; HCF(621,969)
Prime factors of 621 = 3. 3. 3 . 23
Prime factors of 969 = 3 . 17 . 19
Common prime factors: 3
Common prime factors with the lowest exponent: 3^1
HCF = 3
i hope it helps u
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