Math, asked by lakshyajaiswal, 11 months ago

find the greatest number which divides 615 and 963 leaving the remainder 6 in each case​

Answers

Answered by jaspritsingh007
2

Answer:

303 and 319

Step-by-step explanation:

it will leave rhe remainder 6 in both the cases.......

Answered by nmniffco28
1

Answer:

3

Step-by-step explanation:

the greatest no. which divides the 615 and 963 leaving remainder 6 will be

first of all if we add 6 to both no. then they are completely divisible by the no and we know greatest no. which divides is the HCF

therefore; HCF(621,969)

Prime factors of 621 = 3. 3. 3 . 23

Prime factors of 969 = 3 . 17 . 19

Common prime factors: 3

Common prime factors with the lowest exponent: 3^1

HCF = 3

i hope it helps u

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