Math, asked by sbhargav2020, 10 months ago

Find the greatest number which divides 615 and 963, leaving the remainder 6 in each case Please answer

Answers

Answered by tkishika25
1

Answer:

87

Step-by-step explanation:

To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.

Consider HCF be x.

In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases.

609 = 3 x 3 x 29

957= 3 x 11 x 29

⇒ x = 3 x 29 = 87

∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87.

Hope it helps you. Please mark it as BRAINLIST answer.

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