find the Greatest number which divides 615 and 963 ,leaving Reminder 6 in each Case .
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To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.
Consider HCF be x.
In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases.
609 = 3 x 3 x 29
957= 3 x 11 x 29
⇒ x = 3 x 29 = 87
∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87.
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Answer:
In this question, since remainder is six, so we will subtract 6 from 615 and 963 i.e. 609 and 957. Then, we will find the H.C.F. of 609 and 957, that is going to be our answer.
957= 3×11×29
609= 3×3×29
So, H.C.F.= 3×29= 87
hope it will help you
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