Question

find the greatest number which divides 615 and 963 leaving remainder 6 in each case

Answer 1

Because the remainder is 6, we have to find the number that exactly divides 615−6615−6 and 963−6963−6.

Required number = HCF of 609 and 957
6091  957−609        348609(1           −348                       261348(1             −261−−−           87261(3              −261−−−                    06091  957−609        348609(1           −348                       261348(1             −261_           87261(3              −261_                    0

Therefore, the required number is 87. 

Answer 2

Hope this helps you