Question

Find the greatest number which divides 615 and 963 leaving the remainder 6 in each case.

Answer 1

HYE
==================================


we have to  find the largest number which divide 615 and 963 leaving remainder 6 in each case.


let the hcf be A

=> so let us subtract 6 fom both the cases

=>615 - 6 = 609

=> 963-6 = 957

-------------------now lets find the hcf 



=>prime factorisation of 609 = 29*3*3


prime factoristaion of 957 = 29*3*11


now lets take out the common factors from both the cases


=> 29 and 3


x = 29 * 3 = 87
∴87 is the number which will divide 615 and 963 leaving remainder 6 in each case.


========================


hope it helps u.........

Answer 2

Answer:

Hope its helpful for you.....