find the greatest number which divides 615 and 963 leaving the remainder 6 in each case
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Answered by
2
your answere is 95 &143 I hope I help u
Answered by
9
615-6=609
963-6=957
609= 87*7
957 = 87*11
Then the and =87
963-6=957
609= 87*7
957 = 87*11
Then the and =87
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