Question

find the greatest number which divides 68 and 116 to give 4 as remainder in each case

hcf sum plz solve step by step​ plz kardo solve

Answer 1

SOLUTION

Original numbers = 68 , 116

Let the greatest number be x.

According to the question,

Since the numbers leave 4 as remainder on division by x.

•°• Numbers = 68 - 4 = 60 , 116 - 4 = 112

60 = 2² * 3 * 5

112 = 2⁴ * 7

x = HCF(64,112)

x = Common terms with highest power

= 2⁴

x = 16

Therefore, the greatest number is 16.

Answer 2

$\bf{\huge{\underline{\boxed{\sf\purple{Answer:16}}}}}$

$\rule{100}2$

$\huge\underline{\tt Solution:-}$

$\sf\blue{\underline{\underline{Given:}}}$

• A number divides 68 and 116 to give 4 as remainder in each case.

$\sf\blue{\underline{\underline{To\:Find:}}}$

• The greatest number.

$\textsf{\underline{\large{Solution:-}}}$

First of all, subtract 68 and 116  by 4.

we get,

→ 68 = 68 - 4 = 64

→ 116 = 116 - 4 = 112

Now,

Find HCF ( Highest common factor ) in 64 and 112.

→ 64 = 4 × 4 × 4  

→ 112  = 4 × 4  × 7

So, four appears two times in both the numbers.

H.C.F = 4 × 4 = 16.

Therefore,

The greatest number which divides 68 and 116 to give 4 as remainder is 16.

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