Question

find the greatest number which divides 774 247 and 457 leaving remainder 4 5 and 6 respectively

Answer 1

let's take the first no. 774
774-4=770
second no. 247
247-5=242
third no. 457
457-6=451
now let's have the numbers 770,242and451 factor i.e,770=11*2*5*7
242=2*11*11
451=11*41
Thus, The HCF is 11
774/11=(Q) 7 (R)4
247/11=(Q) 24 (R)5
457/11=(Q) 45 (R)6
Hence The greatest number which divides the three numbers leaving the remainder 4,5 and 6 is 11

Answer 2

Hiii friend,


774 - 4 = 770


247 - 5 = 242

And,


457 - 6 = 451


Prime factorisation of 770 = 2 × 5 × 11 × 7

Prime factorisation of 242 = 2 × 11 × 11

Prime factorisation of 451 = 11 × 41


HCF of 770 , 242 and 451 = 11

Hence,



The required Number is the HCF of 770 , 242 and 451 is 11


HOPE IT WILL HELP YOU....... :-)