Math, asked by kundansonu476, 9 months ago

find the greatest number which divides 81 and 292 leaving a remainder 3 in each case.​

Answers

Answered by SaI20065
3

hi

Required number = HCF of  (137−2),(182−2) and (422−2).

Required number = HCF of  (137−2),(182−2) and (422−2).= HCF of (135,180,420)=15.

Required number = HCF of  (137−2),(182−2) and (422−2).= HCF of (135,180,420)=15.The greatest number that will divide 137,182 and 422 leaving a remainder of 2 in each case is 15.

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Answered by sam5532
1

Answer:

LCM of 81 , 292

is 18,396+ 3= 18399

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