Question

find the greatest number which divides 857, 1070 and 1496 leaving 5 as remainder in each case ​

Answer 1

857-5=852

1070-5=1065

1469-5=1465

852=2²*3*71

1065=3*5*71

1465=5*293

HCF =3*71*5

HCF =1065

Answer 2

Answer:

The required number is 213.

Step-by-step explanation:

Given: 857 , 1070 and 1496.

To find: highest No which divides given numbers and leaves 5 as remainder.

Step 1: we subtract 5 from each number

857 - 5 = 852

1070 - 5 = 1065

1496 - 5 = 1491

Step 2: we find HCF (Highest Common Factor) of given number

852 = 2 × 2 × 3 × 71

1065 = 5 × 3 × 71

1491 = 3 × 7 × 71

So, HCF = 3 × 71 = 213

Therefore, The required number is 213.