find the greatest number which divides by 290 and 538 leaves remainder 3 and 5 respectively
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41 is the correct answer
take Hcf of 290-3&538-5
take Hcf of 290-3&538-5
chhayagupta:
pl. show how to find hcf of it
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290 - 3 = 287
538 - 5 = 533
HCF of 287 and 533 is 41
so the greatest number will be 41 which divides 290 and 538 with leaving remainder 3 and 5
538 - 5 = 533
HCF of 287 and 533 is 41
so the greatest number will be 41 which divides 290 and 538 with leaving remainder 3 and 5
how to find hcf of it. pl show
In Which class you are study
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