Question

Find the greatest number which is divides 147,296 and 365 leaving remainder 14,11 and 4 respective​

Answer 1

Answer:

19

Step-by-step explanation:

let the number be x

as 147/x leaves a remainder of 14,

147-14/x will not leave a remainder

133/x leaves no remainder

296/x leaves 11 as remainder

296-11/x leaves no remainder

285/x leaves no remainder

365/x leaves 4 as remainder

365-4/x leaves no remainder

361/x leaves no remainder

a number which divides 133, 285 and 361 completely is the HCF of the numbers

133=7*19

285=3*5*19

361=19*19

so, HCF(133,285, 361)=19

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Answer 2

Answer:

147-14, 296-11, 365-4

Step-by-step explanation:

133,285,361 are the answer of that is given133÷285 HCF is 19÷361 HCF is 19 ,So our solution is 19