Question

find the greatest number which leaves no remainder when it divides 63and 343. full method​

Answer 1

Answer:

1213

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

So by prime factorisation method the L.C.M. of 45 & 63 is 3*3*5*7= 315. ... If leaves remainder when divided by & , then is compSo by prime factorisation method the L.C.M. of 45 & 63 is 3*3*5*7= 315. ... If leaves remainder when divided by & , then is completely divisible by & .

finding out L.C.M. ...

Let the number be “[math]N[/math]”. If [math]N[/math] leaves remainder [math]5[/math]

Find the LCM of 45 and 63 as 45 = 3x3x5 63 = 3x3x7 The LCM = 3x3x5x7 = 315. Add 5 to 315 ... Moreletely divisible by & .

For such type of questions you need nothing to do all you need to know is finding out L.C.M. ...

Let the number be “[math]N[/math]”. If [math]N[/math] leaves remainder [math]5[/math] ...

Find the LCM of 45 and 63 as 45 = 3x3x5 63 = 3x3x7 The LCM = 3x3x5x7 = 315. Add 5 to 315 ...