Question

find the greatest number which on divided 62,132,237to leaves the same remainder in each case​

Answer 1

Answer:

To find HCF first we have to simply HCF of difference of each term

H.C.F of (132-62) (237-132) (237-62)

H.C.F of (70) (105) (175)

H.C.F. of (2×5×7) (3×5×7) (5×5×7)

so the HCF of these numbers is

5×7= 35