Find the greatest number which on dividing 1654 and 2153,leaves a remainder of 24 and 23 respectively
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The required number will be the H.C.F of (120 - 5), (165 - 4) and (210 - 3) i.e. H.C.F. of 115
161 and 207
∴ Required number = H.C.F. of 115, 161 and 207 = 23
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