Find the greatest number which when divided by 181 and 236 leaves a remainder of 5 in each case
Answers
Answer:
try to devide 236 with 181and then see the remaiinder if the remainder is greater than your and wer cam and if not than try any other devisible to 181
The greatest number which when divided by 181 and 236 leaves a remainder of 5 in each case is 11
Solution:
Given numbers are 181 and 236
We have to find the greatest number which when divided by 181 and 236 leaves a remainder of 5 in each case
Subtract 5 from each given numbers
181 - 5 = 176
236 - 5 = 231
Now find greatest common factor of 176 and 231
Greatest common factor of 176 and 231:
The factors of 176 are: 1, 2, 4, 8, 11, 16, 22, 44, 88, 176
The factors of 231 are: 1, 3, 7, 11, 21, 33, 77, 231
Then the greatest common factor is 11
Thus the greatest number which when divided by 181 and 236 leaves a remainder of 5 in each case is 11
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