Question

Find the greatest number which when divided by 181 and 236 leaves a remainder of 5 in each case

Answer 1

Answer:

try to devide 236 with 181and then see the remaiinder if the remainder is greater than your and wer cam and if not than try any other devisible to 181

Answer 2

The greatest number which when divided by 181 and 236 leaves a remainder of 5 in each case  is 11

Solution:

Given numbers are 181 and 236

We have to find the greatest number which when divided by 181 and 236 leaves a remainder of 5 in each case

Subtract 5 from each given numbers

181 - 5 = 176

236 - 5 = 231

Now find greatest common factor of 176 and 231

Greatest common factor of 176 and 231:

The factors of 176 are: 1, 2, 4, 8, 11, 16, 22, 44, 88, 176

The factors of 231 are: 1, 3, 7, 11, 21, 33, 77, 231

Then the greatest common factor is 11

Thus the greatest number which when divided by 181 and 236 leaves a remainder of 5 in each case  is 11

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