Find the greatest number which when divided by 181 and 236 leave a remainder of five in each case
Answers
Answer:
The greatest number which when divided by 181 and 236 leaves a remainder of 5 in each case is 11.
The greatest number which when divided by 181 and 236 leave a remainder of five in each case is 11
Given :
The numbers 181 and 236
To find :
The greatest number which when divided by 181 and 236 leave a remainder of five in each case
Solution :
Step 1 of 2 :
Write down the given numbers
Here the given numbers are 181 and 236
Step 2 of 2 :
Find the greatest number which when divided by 181 and 236 leave a remainder of five in each case
The greatest number which when divided by 181 and 236 leave a remainder of five in each case
= The greatest number which divides (181 - 5) and (236 - 5) completely
= The greatest number which divides 176 and 231 completely
= HCF of 176 and 231
We find HCF of 176 and 231
176 = 2 × 2 × 2 × 2 × 11
231 = 3 × 7 × 11
∴ HCF of 176 and 231 = 11
Hence the greatest number which when divided by 181 and 236 leave a remainder of five in each case is 11
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