Find the greatest number which when divided by 322,162 and 402 leave a remainder 2 in each case?
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322=322-2=320
162=162-2=160
402=402-2=420
HCF of 320 and 160
320=160×2
therefore, HCF (320and 160)=160
HCF of 160 and 400
400=160×2+80
160=80×2
therefore, HCF (400and 160)= 80
: when the above three no. be divided by 80 they will leave a remainder of 2
162=162-2=160
402=402-2=420
HCF of 320 and 160
320=160×2
therefore, HCF (320and 160)=160
HCF of 160 and 400
400=160×2+80
160=80×2
therefore, HCF (400and 160)= 80
: when the above three no. be divided by 80 they will leave a remainder of 2
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