Question

find the greatest number which when divided by 60 and 90 leaves 3 as the remainder in each case

Answer 1

Answer:

183 is correct answer.

Step-by-step explanation:

Required no. = (LCM of 15, 20 & 30) + 3

Required no. = 180 + 3

Required no. = 183 is correct answer.

Answer 2

prime factorization of 60=2*3*5

prime factorization of 90=2*3*5

product of 2*3*5=30

so the greatest no is 30.

when 3 will be added to 60 and 90 then number will be 63, 93.

in case of division simply find out prime factorization of given no without adding or subtracting remainder part.