Question

find the greatest number which when divides 286,1250 leaving remainder 10,8 respectively

Answer 1

well the question here asks for you to find the HCF(highest common factor) as it says "the greatest number which divides"
Now to solve this, first you need to subtract the given remainders from their given respective terms :
286 - 10 = 276
and 1250 - 8 = 1242
Now as we have these two new numbers, we need to find the HCF of them :
by using Euclid's division lemma,
a=bq+r , where b>r>or=0
(this can also be solved by taking out the common factors of both the numbers)
in this case, a=1242 , b=276
1242 = 276 × 4 + 138
276=138×2+0
as the remainder is now zero, therefore 138 is the required number

^_^ hope this helps!

Answer 2

Answer:

I hope it helps!

Step-by-step explanation:

50-6=44

250-8=242

FACTORS OF 44 AND 242

44=2x2x11

242=2x11x11

HCF=2x11

       =22

HENCE THE GREATEST NUMBER IS 22...