Find the greatest number which when it divides 367, 135 and 259 will leave the same remainder in
each case.
Answers
Answer:
Answer. Answer: The largest number would be 6. 150, 180, and 144. We need to find the largest number which divides the above numbers and leaves the same remainder in each case.
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Given:
The greatest number which when it divides 367, 135 and 259 will leave the same remainder in each case.
To find:
The greatest number
Solution:
(1). We are given 3 numbers 367, 135 & 259 each of which when divided by the greatest number gives the same remainder in each case which is not given to us.
(2). So, we will find the difference between each pair.
367 - 135 = 232
367 - 259 = 108
259 - 135 = 124
(3). Now we will find the H.C.F. of 232, 108 & 124 by using the prime factorisation method
232 = 2 × 2 × 2 × 29
108 = 2 × 2 × 3 × 3 × 3
124 = 2 × 2 × 31
∴ H.C.F. (232, 108 & 124) = 2 × 2 = 4
Thus, the greatest number which when it divides 367, 135 and 259 will leave the same remainder in each case is → 4.
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