find the greatest number which will divide 148 and 249 to leave reminder 8 and 18 respectively
Answers
Answer:
u do yourself time give me example
Step-by-step explanation:
Remainder in case of 148 = 4 Number = 148 - 4 =
144
Remainder in case of 246 = 6
Number = 246 6 = 240 Remainder in case of 623 = 11
Number = 623 - 11 = 612 Now, we have find the H.C.F. of 144. 240 and 612 2 1 144, 240, 612 2 1 72, 120, 306 3 36, 60, 153 | 12, 20, 51
and 612 2 | 144, 240, 612 21 72, 120, 306 3 | 36, 60, 153 | 12, 20, 51 H.C.F. of 144, 240 and 612 = 2*2*3 = 12
Therefore, the required number is 12 that will divide 148, 246 and 623 leaving remainders 4, 6 and 11 respectively.
Answer:
7
Step-by-step explanation:
To find that number, we will subtract the remainder and then divide by the least divisor... and then find it's HCF!
=>(i) (148 - 8)/2 = 140/2 = 70
(ii) (249-18)/3 = 231/3 = 77 (Why 3? Because the lowest divisor is 3 and
not 2 here)
Here, the greatest common factor is 7, therefore the Number is 7!
I hope you get it!