find the greatest number which will divide (22,86,129) leaving remainder 1,2,3 respectively
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The answer is 21
because when we divide 22 by 21, the reminder is 1 (21*1 = 21)
when we divide 86 by 21, the remainder is 2 (21*4 = 84)
when we divide 129 by 21, the remainder is 3 (21*6 = 126)
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this is the rong answer the answer of the question is 27
how it will be 27??
it answer is 21
if 22 is divided by 27, then the remainder will be 22, if it is with 86 then it will be 5 and with 129, it will be 11
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22-1=21
86-2=84
129-3=126
hcf of 21 ,84,126
21 ans
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