Question

Find the greatest number which will divide 4003, 4126 and
4249, leaving the same remainder in each case.​

Answer 1

Answer:

222222222222222222222222ssssss

Answer 2

$\huge \dag \:{ \underline{ \boxed{ \mathfrak{ \purple{Answer}}}}}$

Greatest number with which if we divide P, Q, R and it leaves same remainder in each case. Number is of form = HCF of (P - Q), (P - R)

Therefore, HCF of (4126 - 4003), (4249 - 4003) = HCF of 123, 246 = 41.

[Taken for Positive result]

Detailed Explanation:

The numbers can be written as,

4003 = AX + P where P = Remainder

4126 = BX + P

4249 = CX + P

(B - A) × X = 123

(C - B) × X = 246

Thus the X is factor of 123 and 246