Find the greatest number which will divide 410, 751, 1030 so as to leave the se remainder
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Answered by
3
Answer:
Step-by-step explanation:
to find the no. dividing 410 , 751 , 1040 leaving remainder 7, the HCF of the no. will be (410-7), (751-7), (1030-7)
the h.c.f. of 403, 744, 1023 is 31
hence the no is 31
Answered by
0
Answer:
Step-by-step explanation:
Step-by-step explanation:
to find the no. dividing 410 , 751 , 1040 leaving remainder 7, the HCF of the no. will be (410-7), (751-7), (1030-7)
the h.c.f. of 403, 744, 1023 is 31
hence the no is 31
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