Find the greatest number which will
divides 625and 1433 leaving remainder 5 and 3 respectively
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2
Answer:
10
Step-by-step explanation:
As it leaves a remainder of 5 when dividing into 625, the number we want must be a factor of 620.
As it leaves a remainder of 3 when dividing into 1433, the number we want must be a factor of 1430.
So we are asked for the highest common factor of 620 and 1430.
The prime factorizations are
620 = 2 × 2 × 5 × 31
1430 = 2 × 5 × 11 × 13
So the higest common factor is 2 × 5 = 10.
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